Education
About Us
Working with TipRanks
Follow Us
Patrick Macdougall Insider Profile
4 Followers
Patrick Macdougall, Director at Jade Road Investments , holds 594.12K shares in Jade Road Investments (Ticker: GB:JADE). Most recently, Patrick Macdougall Bought 300,000 shares of Jade Road Investments on Dec 31, 2012 for an estimated value of $30.27K.
Patrick Macdougall has not reported sufficient informative transactions and therefore cannot be ranked.
Time Frame
Compare to
Insider Holdings
100.00%
A breakdown of Patrick Macdougall's holdings
Insider Roles
Director
Roles that Patrick Macdougall holds in companies
Most Profitable Insider Trade
Currently, no data available
The most profitable trade made by Patrick Macdougall
Patrick Macdougall's Trading History
List of latest transactions for each holding click on a transaction to see Patrick Macdougall's performance on stock
You May Also Like
Patrick Macdougall insider profile FAQ
What is the percentage of profitable transactions made by Patrick Macdougall?
The percentage of profitable transactions made by Patrick Macdougall is ―.
What is the average return per transaction made by Patrick Macdougall?
The average return per transaction made by Patrick Macdougall is ―.
What stocks does Patrick Macdougall hold?
Patrick Macdougall holds: GB:JADE stocks.
What was Patrick Macdougall’s latest transaction?
Patrick Macdougall latest transaction was an Informative Buy of $30.27K.
What was Patrick Macdougall's most profitable transaction?
Patrick Macdougall’s most profitable transaction was an Uninformative Buy of stock on ―. The return on the trade was ―.
What is Patrick Macdougall's role in Jade Road Investments ?
Patrick Macdougall's role in Jade Road Investments is Director.
How can I follow the stock ratings of top corporate insiders?
Head over to our Expert Center to see a list of the Top 100 corporate insiders and follow the corporate insiders of your choice. Visit their profiles for more details about their stock transactions and see how they perform on a stock-by-stock basis.